sin(2x)-cos(4x)=1

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Solution for sin(2x)-cos(4x)=1 equation:


Simplifying
sin(2x) + -1cos(4x) = 1

Remove parenthesis around (2x)
ins * 2x + -1cos(4x) = 1

Reorder the terms for easier multiplication:
2ins * x + -1cos(4x) = 1

Multiply ins * x
2insx + -1cos(4x) = 1

Remove parenthesis around (4x)
2insx + -1cos * 4x = 1

Reorder the terms for easier multiplication:
2insx + -1 * 4cos * x = 1

Multiply -1 * 4
2insx + -4cos * x = 1

Multiply cos * x
2insx + -4cosx = 1

Reorder the terms:
-4cosx + 2insx = 1

Solving
-4cosx + 2insx = 1

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2insx' to each side of the equation.
-4cosx + 2insx + -2insx = 1 + -2insx

Combine like terms: 2insx + -2insx = 0
-4cosx + 0 = 1 + -2insx
-4cosx = 1 + -2insx

Divide each side by '-4osx'.
c = -0.25o-1s-1x-1 + 0.5ino-1

Simplifying
c = -0.25o-1s-1x-1 + 0.5ino-1

Reorder the terms:
c = 0.5ino-1 + -0.25o-1s-1x-1

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