sin(2x)-cos(x)-2sin(x)+1=0

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Solution for sin(2x)-cos(x)-2sin(x)+1=0 equation:


Simplifying
sin(2x) + -1cos(x) + -2sin(x) + 1 = 0

Remove parenthesis around (2x)
ins * 2x + -1cos(x) + -2sin(x) + 1 = 0

Reorder the terms for easier multiplication:
2ins * x + -1cos(x) + -2sin(x) + 1 = 0

Multiply ins * x
2insx + -1cos(x) + -2sin(x) + 1 = 0

Multiply cos * x
2insx + -1cosx + -2sin(x) + 1 = 0

Multiply ins * x
2insx + -1cosx + -2insx + 1 = 0

Reorder the terms:
1 + -1cosx + 2insx + -2insx = 0

Combine like terms: 2insx + -2insx = 0
1 + -1cosx + 0 = 0
1 + -1cosx = 0

Solving
1 + -1cosx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1cosx = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1cosx = 0 + -1
-1cosx = 0 + -1

Combine like terms: 0 + -1 = -1
-1cosx = -1

Divide each side by '-1osx'.
c = o-1s-1x-1

Simplifying
c = o-1s-1x-1

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