sin(2x)-sin(x)-2cos(x)+1=0

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Solution for sin(2x)-sin(x)-2cos(x)+1=0 equation:


Simplifying
sin(2x) + -1sin(x) + -2cos(x) + 1 = 0

Remove parenthesis around (2x)
ins * 2x + -1sin(x) + -2cos(x) + 1 = 0

Reorder the terms for easier multiplication:
2ins * x + -1sin(x) + -2cos(x) + 1 = 0

Multiply ins * x
2insx + -1sin(x) + -2cos(x) + 1 = 0

Multiply ins * x
2insx + -1insx + -2cos(x) + 1 = 0

Multiply cos * x
2insx + -1insx + -2cosx + 1 = 0

Reorder the terms:
1 + -2cosx + 2insx + -1insx = 0

Combine like terms: 2insx + -1insx = 1insx
1 + -2cosx + 1insx = 0

Solving
1 + -2cosx + 1insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -2cosx + -1 + 1insx = 0 + -1

Reorder the terms:
1 + -1 + -2cosx + 1insx = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -2cosx + 1insx = 0 + -1
-2cosx + 1insx = 0 + -1

Combine like terms: 0 + -1 = -1
-2cosx + 1insx = -1

Add '-1insx' to each side of the equation.
-2cosx + 1insx + -1insx = -1 + -1insx

Combine like terms: 1insx + -1insx = 0
-2cosx + 0 = -1 + -1insx
-2cosx = -1 + -1insx

Divide each side by '-2osx'.
c = 0.5o-1s-1x-1 + 0.5ino-1

Simplifying
c = 0.5o-1s-1x-1 + 0.5ino-1

Reorder the terms:
c = 0.5ino-1 + 0.5o-1s-1x-1

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