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D( x )
cos(4*x) = 0
cos(4*x) = 0
cos(4*x) = 0
cos(4*x) = 0 <=> 4*x = pi*k_1+pi/2 i k_1 należy do I
t_1 = pi*k_1+pi/2
4*x-t_1 = 0
4*x-t_1 = 0 // + t_1
4*x = t_1 // : 4
x = t_1/4
x = pi*k_1+pi/2/4 i k_1 należy do I
x in {( -oo : +oo ) / < pi*k_1+pi/2/4 : pi*k_1+pi/2/4 >} i k_1 -> {I}
sin(2*x)/cos(4*x) = 0
sin(2*x)/cos(4*x) = 0 // * cos(4*x)
sin(2*x) = 0
sin(2*x) = 0 <=> 2*x = pi*k_1 i k_1 należy do I
t_1 = pi*k_1
2*x-t_1 = 0
2*x-t_1 = 0 // + t_1
2*x = t_1 // : 2
x = t_1/2
x = pi*k_1/2 i k_1 należy do I
x = pi*k_1/2
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