sin(2x)cos(x)+cos(2x)sin(x)=1

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Solution for sin(2x)cos(x)+cos(2x)sin(x)=1 equation: 


Simplifying
sin(2x) * cos(x) + cos(2x) * sin(x) = 1

Remove parenthesis around (2x)
ins * 2x * cos(x) + cos(2x) * sin(x) = 1

Reorder the terms for easier multiplication:
2ins * x * cos * x + cos(2x) * sin(x) = 1

Multiply ins * x
2insx * cos * x + cos(2x) * sin(x) = 1

Multiply insx * cos
2cinos2x * x + cos(2x) * sin(x) = 1

Multiply cinos2x * x
2cinos2x2 + cos(2x) * sin(x) = 1

Remove parenthesis around (2x)
2cinos2x2 + cos * 2x * sin(x) = 1

Reorder the terms for easier multiplication:
2cinos2x2 + 2cos * x * ins * x = 1

Multiply cos * x
2cinos2x2 + 2cosx * ins * x = 1

Multiply cosx * ins
2cinos2x2 + 2cinos2x * x = 1

Multiply cinos2x * x
2cinos2x2 + 2cinos2x2 = 1

Combine like terms: 2cinos2x2 + 2cinos2x2 = 4cinos2x2
4cinos2x2 = 1

Solving
4cinos2x2 = 1

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '4inos2x2'.
c = 0.25i-1n-1o-1s-2x-2

Simplifying
c = 0.25i-1n-1o-1s-2x-2

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