sin(3x)+sin(7x)=4cos(2x)

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Solution for sin(3x)+sin(7x)=4cos(2x) equation:


Simplifying
sin(3x) + sin(7x) = 4cos(2x)

Remove parenthesis around (3x)
ins * 3x + sin(7x) = 4cos(2x)

Reorder the terms for easier multiplication:
3ins * x + sin(7x) = 4cos(2x)

Multiply ins * x
3insx + sin(7x) = 4cos(2x)

Remove parenthesis around (7x)
3insx + ins * 7x = 4cos(2x)

Reorder the terms for easier multiplication:
3insx + 7ins * x = 4cos(2x)

Multiply ins * x
3insx + 7insx = 4cos(2x)

Combine like terms: 3insx + 7insx = 10insx
10insx = 4cos(2x)

Remove parenthesis around (2x)
10insx = 4cos * 2x

Reorder the terms for easier multiplication:
10insx = 4 * 2cos * x

Multiply 4 * 2
10insx = 8cos * x

Multiply cos * x
10insx = 8cosx

Solving
10insx = 8cosx

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Divide each side by '10nsx'.
i = 0.8cn-1o

Simplifying
i = 0.8cn-1o

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