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D( x )
cos(x) = 0
cos(x) = 0
cos(x) = 0
cos(x) = 0 <=> x = pi*k_1+pi/2 i k_1 należy do I
t_1 = pi*k_1+pi/2
x-t_1 = 0
x-t_1 = 0 // + t_1
x = t_1
x = pi*k_1+pi/2 i k_1 należy do I
x in {( -oo : +oo ) / < pi*k_1+pi/2 : pi*k_1+pi/2 >} i k_1 -> {I}
sin(3*x)/cos(x) = 0
sin(3*x)/cos(x) = 0 // * cos(x)
sin(3*x) = 0
sin(3*x) = 0 <=> 3*x = pi*k_1 i k_1 należy do I
t_1 = pi*k_1
3*x-t_1 = 0
3*x-t_1 = 0 // + t_1
3*x = t_1 // : 3
x = t_1/3
x = pi*k_1/3 i k_1 należy do I
x = pi*k_1/3
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