sin(3x)cos(2x)-sin(2x)cos(3x)=0

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Solution for sin(3x)cos(2x)-sin(2x)cos(3x)=0 equation:


Simplifying
sin(3x) * cos(2x) + -1sin(2x) * cos(3x) = 0

Remove parenthesis around (3x)
ins * 3x * cos(2x) + -1sin(2x) * cos(3x) = 0

Remove parenthesis around (2x)
ins * 3x * cos * 2x + -1sin(2x) * cos(3x) = 0

Reorder the terms for easier multiplication:
3 * 2ins * x * cos * x + -1sin(2x) * cos(3x) = 0

Multiply 3 * 2
6ins * x * cos * x + -1sin(2x) * cos(3x) = 0

Multiply ins * x
6insx * cos * x + -1sin(2x) * cos(3x) = 0

Multiply insx * cos
6cinos2x * x + -1sin(2x) * cos(3x) = 0

Multiply cinos2x * x
6cinos2x2 + -1sin(2x) * cos(3x) = 0

Remove parenthesis around (2x)
6cinos2x2 + -1ins * 2x * cos(3x) = 0

Remove parenthesis around (3x)
6cinos2x2 + -1ins * 2x * cos * 3x = 0

Reorder the terms for easier multiplication:
6cinos2x2 + -1 * 2 * 3ins * x * cos * x = 0

Multiply -1 * 2
6cinos2x2 + -2 * 3ins * x * cos * x = 0

Multiply -2 * 3
6cinos2x2 + -6ins * x * cos * x = 0

Multiply ins * x
6cinos2x2 + -6insx * cos * x = 0

Multiply insx * cos
6cinos2x2 + -6cinos2x * x = 0

Multiply cinos2x * x
6cinos2x2 + -6cinos2x2 = 0

Combine like terms: 6cinos2x2 + -6cinos2x2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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