sin(3x-(pi/2))

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Solution for sin(3x-(pi/2)) equation: 


x in (-oo:+oo)

sin(3*x-(pi/2)) = 0

sin(3*x-(pi/2)) = 0  <=>  3*x-(pi/2) = pi*k_1 i k_1 należy do I

t_1 = pi*k_1

3*x-t_1-(pi/2) = 0

3*x-t_1-(pi/2) = 0 // + -t_1-(pi/2)

3*x = -(-t_1-(pi/2)) // : 3

x = (-(-t_1-(pi/2)))/3

x = (t_1+pi/2)/3

x = (pi*k_1+pi/2)/3 i k_1 należy do I

x = (pi*k_1+pi/2)/3

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