sin(5x)+cos(4x)=2

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Solution for sin(5x)+cos(4x)=2 equation:


Simplifying
sin(5x) + cos(4x) = 2

Remove parenthesis around (5x)
ins * 5x + cos(4x) = 2

Reorder the terms for easier multiplication:
5ins * x + cos(4x) = 2

Multiply ins * x
5insx + cos(4x) = 2

Remove parenthesis around (4x)
5insx + cos * 4x = 2

Reorder the terms for easier multiplication:
5insx + 4cos * x = 2

Multiply cos * x
5insx + 4cosx = 2

Reorder the terms:
4cosx + 5insx = 2

Solving
4cosx + 5insx = 2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5insx' to each side of the equation.
4cosx + 5insx + -5insx = 2 + -5insx

Combine like terms: 5insx + -5insx = 0
4cosx + 0 = 2 + -5insx
4cosx = 2 + -5insx

Divide each side by '4osx'.
c = 0.5o-1s-1x-1 + -1.25ino-1

Simplifying
c = 0.5o-1s-1x-1 + -1.25ino-1

Reorder the terms:
c = -1.25ino-1 + 0.5o-1s-1x-1

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