sin(5x)-cos(2x)+4=0

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Solution for sin(5x)-cos(2x)+4=0 equation:


Simplifying
sin(5x) + -1cos(2x) + 4 = 0

Remove parenthesis around (5x)
ins * 5x + -1cos(2x) + 4 = 0

Reorder the terms for easier multiplication:
5ins * x + -1cos(2x) + 4 = 0

Multiply ins * x
5insx + -1cos(2x) + 4 = 0

Remove parenthesis around (2x)
5insx + -1cos * 2x + 4 = 0

Reorder the terms for easier multiplication:
5insx + -1 * 2cos * x + 4 = 0

Multiply -1 * 2
5insx + -2cos * x + 4 = 0

Multiply cos * x
5insx + -2cosx + 4 = 0

Reorder the terms:
4 + -2cosx + 5insx = 0

Solving
4 + -2cosx + 5insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -2cosx + -4 + 5insx = 0 + -4

Reorder the terms:
4 + -4 + -2cosx + 5insx = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -2cosx + 5insx = 0 + -4
-2cosx + 5insx = 0 + -4

Combine like terms: 0 + -4 = -4
-2cosx + 5insx = -4

Add '-5insx' to each side of the equation.
-2cosx + 5insx + -5insx = -4 + -5insx

Combine like terms: 5insx + -5insx = 0
-2cosx + 0 = -4 + -5insx
-2cosx = -4 + -5insx

Divide each side by '-2osx'.
c = 2o-1s-1x-1 + 2.5ino-1

Simplifying
c = 2o-1s-1x-1 + 2.5ino-1

Reorder the terms:
c = 2.5ino-1 + 2o-1s-1x-1

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