sin(5x)-cos(2x)+sin(x)=0

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Solution for sin(5x)-cos(2x)+sin(x)=0 equation:


Simplifying
sin(5x) + -1cos(2x) + sin(x) = 0

Remove parenthesis around (5x)
ins * 5x + -1cos(2x) + sin(x) = 0

Reorder the terms for easier multiplication:
5ins * x + -1cos(2x) + sin(x) = 0

Multiply ins * x
5insx + -1cos(2x) + sin(x) = 0

Remove parenthesis around (2x)
5insx + -1cos * 2x + sin(x) = 0

Reorder the terms for easier multiplication:
5insx + -1 * 2cos * x + sin(x) = 0

Multiply -1 * 2
5insx + -2cos * x + sin(x) = 0

Multiply cos * x
5insx + -2cosx + sin(x) = 0

Multiply ins * x
5insx + -2cosx + insx = 0

Reorder the terms:
-2cosx + 5insx + insx = 0

Combine like terms: 5insx + insx = 6insx
-2cosx + 6insx = 0

Solving
-2cosx + 6insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6insx' to each side of the equation.
-2cosx + 6insx + -6insx = 0 + -6insx

Combine like terms: 6insx + -6insx = 0
-2cosx + 0 = 0 + -6insx
-2cosx = 0 + -6insx
Remove the zero:
-2cosx = -6insx

Divide each side by '-2osx'.
c = 3ino-1

Simplifying
c = 3ino-1

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