sin(5x)cos(2x)-cos(5x)sin(2x)=0

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Solution for sin(5x)cos(2x)-cos(5x)sin(2x)=0 equation:


Simplifying
sin(5x) * cos(2x) + -1cos(5x) * sin(2x) = 0

Remove parenthesis around (5x)
ins * 5x * cos(2x) + -1cos(5x) * sin(2x) = 0

Remove parenthesis around (2x)
ins * 5x * cos * 2x + -1cos(5x) * sin(2x) = 0

Reorder the terms for easier multiplication:
5 * 2ins * x * cos * x + -1cos(5x) * sin(2x) = 0

Multiply 5 * 2
10ins * x * cos * x + -1cos(5x) * sin(2x) = 0

Multiply ins * x
10insx * cos * x + -1cos(5x) * sin(2x) = 0

Multiply insx * cos
10cinos2x * x + -1cos(5x) * sin(2x) = 0

Multiply cinos2x * x
10cinos2x2 + -1cos(5x) * sin(2x) = 0

Remove parenthesis around (5x)
10cinos2x2 + -1cos * 5x * sin(2x) = 0

Remove parenthesis around (2x)
10cinos2x2 + -1cos * 5x * ins * 2x = 0

Reorder the terms for easier multiplication:
10cinos2x2 + -1 * 5 * 2cos * x * ins * x = 0

Multiply -1 * 5
10cinos2x2 + -5 * 2cos * x * ins * x = 0

Multiply -5 * 2
10cinos2x2 + -10cos * x * ins * x = 0

Multiply cos * x
10cinos2x2 + -10cosx * ins * x = 0

Multiply cosx * ins
10cinos2x2 + -10cinos2x * x = 0

Multiply cinos2x * x
10cinos2x2 + -10cinos2x2 = 0

Combine like terms: 10cinos2x2 + -10cinos2x2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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