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x in (-oo:+oo)
sin((pi/3)*x) = 0
sin((pi/3)*x) = 0 <=> (pi/3)*x = pi*k_1 i k_1 należy do I
t_1 = pi*k_1
(pi/3)*x-t_1 = 0
(pi/3)*x-t_1 = 0 // + t_1
(pi/3)*x = t_1 // : pi/3
x = t_1/(pi/3)
x = pi*k_1/(pi/3) i k_1 należy do I
x = pi*k_1/(pi/3)
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