If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2-(3*abs(x+6)) > 0
tan(2*x^3+1)/6
-12*(h/3) = 0
T/50 = 20
tan(2*x^3+1)/(6*x^2)
| x=4-0.5(x+2) | | 0.5x+x(x-0.5)=x(x-5)+10 | | 118+8x=148+5x | | 8x-2(x-4)-1=7x-5 | | 6n+(-11)=19 | | 21-2k=5 | | 100[0.04(q+4)]= | | -5(n+7)=-7n-19 | | .2X+.6y=80 | | 48-2r=2 | | h/3*-12 | | 3x*20=15*32 | | T/50=20 | | 9c+-9=45 | | 10=15+23t-5t^2 | | 0.06+0.9[0.12-0.06]= | | 3p-57=42 | | 21+2.5w=6+5.7w-3.2w+15 | | 3x+10=4(2x-3) | | -16X-9=x | | 8-5n=43 | | -4(5x+8)+4=32-8x | | 3x/2x-1=3 | | (2x+10)=110 | | 0.625f=4.375 | | k^2+3k-28=0 | | 1/2(6n-12)=3/4(4-8n) | | 6r+(21+13r)=87+(11r-10) | | 0.625*7=f | | 2(x+12)=2(x-2+16) | | 0.05x+x=1.05 | | ln(x+3)-ln(x-6)=4 |