sin(x)(2cos(x)+1)=0

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Solution for sin(x)(2cos(x)+1)=0 equation:


Simplifying
sin(x)(2cos(x) + 1) = 0

Multiply cos * x
ins * x(2cosx + 1) = 0

Reorder the terms:
ins * x(1 + 2cosx) = 0

Multiply ins * x
insx(1 + 2cosx) = 0
(1 * insx + 2cosx * insx) = 0

Reorder the terms:
(2cinos2x2 + 1insx) = 0
(2cinos2x2 + 1insx) = 0

Solving
2cinos2x2 + 1insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1insx' to each side of the equation.
2cinos2x2 + 1insx + -1insx = 0 + -1insx

Combine like terms: 1insx + -1insx = 0
2cinos2x2 + 0 = 0 + -1insx
2cinos2x2 = 0 + -1insx
Remove the zero:
2cinos2x2 = -1insx

Divide each side by '2inos2x2'.
c = -0.5o-1s-1x-1

Simplifying
c = -0.5o-1s-1x-1

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