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Simplifying sin(x)(2cos(x) + 1) = 0 Multiply cos * x ins * x(2cosx + 1) = 0 Reorder the terms: ins * x(1 + 2cosx) = 0 Multiply ins * x insx(1 + 2cosx) = 0 (1 * insx + 2cosx * insx) = 0 Reorder the terms: (2cinos2x2 + 1insx) = 0 (2cinos2x2 + 1insx) = 0 Solving 2cinos2x2 + 1insx = 0 Solving for variable 'c'. Move all terms containing c to the left, all other terms to the right. Add '-1insx' to each side of the equation. 2cinos2x2 + 1insx + -1insx = 0 + -1insx Combine like terms: 1insx + -1insx = 0 2cinos2x2 + 0 = 0 + -1insx 2cinos2x2 = 0 + -1insx Remove the zero: 2cinos2x2 = -1insx Divide each side by '2inos2x2'. c = -0.5o-1s-1x-1 Simplifying c = -0.5o-1s-1x-1
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