sin(x)*(sin(x)+2cos(x))=2x-2pi

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Solution for sin(x)*(sin(x)+2cos(x))=2x-2pi equation:


Simplifying
sin(x)(sin(x) + 2cos(x)) = 2x + -2pi

Multiply ins * x
ins * x(insx + 2cos(x)) = 2x + -2pi

Multiply cos * x
ins * x(insx + 2cosx) = 2x + -2pi

Reorder the terms:
ins * x(2cosx + insx) = 2x + -2pi

Multiply ins * x
insx(2cosx + insx) = 2x + -2pi
(2cosx * insx + insx * insx) = 2x + -2pi
(2cinos2x2 + i2n2s2x2) = 2x + -2pi

Reorder the terms:
2cinos2x2 + i2n2s2x2 = -2ip + 2x

Solving
2cinos2x2 + i2n2s2x2 = -2ip + 2x

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1i2n2s2x2' to each side of the equation.
2cinos2x2 + i2n2s2x2 + -1i2n2s2x2 = -2ip + -1i2n2s2x2 + 2x

Combine like terms: i2n2s2x2 + -1i2n2s2x2 = 0
2cinos2x2 + 0 = -2ip + -1i2n2s2x2 + 2x
2cinos2x2 = -2ip + -1i2n2s2x2 + 2x

Divide each side by '2inos2x2'.
c = -1n-1o-1ps-2x-2 + -0.5ino-1 + i-1n-1o-1s-2x-1

Simplifying
c = -1n-1o-1ps-2x-2 + -0.5ino-1 + i-1n-1o-1s-2x-1

Reorder the terms:
c = i-1n-1o-1s-2x-1 + -0.5ino-1 + -1n-1o-1ps-2x-2

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