sin(x)cos(2x)+cos(x)sin(2x)=0

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Solution for sin(x)cos(2x)+cos(x)sin(2x)=0 equation:


Simplifying
sin(x) * cos(2x) + cos(x) * sin(2x) = 0

Remove parenthesis around (2x)
ins * x * cos * 2x + cos(x) * sin(2x) = 0

Reorder the terms for easier multiplication:
2ins * x * cos * x + cos(x) * sin(2x) = 0

Multiply ins * x
2insx * cos * x + cos(x) * sin(2x) = 0

Multiply insx * cos
2cinos2x * x + cos(x) * sin(2x) = 0

Multiply cinos2x * x
2cinos2x2 + cos(x) * sin(2x) = 0

Remove parenthesis around (2x)
2cinos2x2 + cos * x * ins * 2x = 0

Reorder the terms for easier multiplication:
2cinos2x2 + 2cos * x * ins * x = 0

Multiply cos * x
2cinos2x2 + 2cosx * ins * x = 0

Multiply cosx * ins
2cinos2x2 + 2cinos2x * x = 0

Multiply cinos2x * x
2cinos2x2 + 2cinos2x2 = 0

Combine like terms: 2cinos2x2 + 2cinos2x2 = 4cinos2x2
4cinos2x2 = 0

Solving
4cinos2x2 = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '4'.
cinos2x2 = 0

Simplifying
cinos2x2 = 0

The solution to this equation could not be determined.

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