sin(x)cos(4x)+sin(4x)cos(x)=1

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Solution for sin(x)cos(4x)+sin(4x)cos(x)=1 equation: 


Simplifying
sin(x) * cos(4x) + sin(4x) * cos(x) = 1

Remove parenthesis around (4x)
ins * x * cos * 4x + sin(4x) * cos(x) = 1

Reorder the terms for easier multiplication:
4ins * x * cos * x + sin(4x) * cos(x) = 1

Multiply ins * x
4insx * cos * x + sin(4x) * cos(x) = 1

Multiply insx * cos
4cinos2x * x + sin(4x) * cos(x) = 1

Multiply cinos2x * x
4cinos2x2 + sin(4x) * cos(x) = 1

Remove parenthesis around (4x)
4cinos2x2 + ins * 4x * cos(x) = 1

Reorder the terms for easier multiplication:
4cinos2x2 + 4ins * x * cos * x = 1

Multiply ins * x
4cinos2x2 + 4insx * cos * x = 1

Multiply insx * cos
4cinos2x2 + 4cinos2x * x = 1

Multiply cinos2x * x
4cinos2x2 + 4cinos2x2 = 1

Combine like terms: 4cinos2x2 + 4cinos2x2 = 8cinos2x2
8cinos2x2 = 1

Solving
8cinos2x2 = 1

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '8inos2x2'.
c = 0.125i-1n-1o-1s-2x-2

Simplifying
c = 0.125i-1n-1o-1s-2x-2

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