sin(x)n+cos(2x)=1

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Solution for sin(x)n+cos(2x)=1 equation:


Simplifying
sin(x) * n + cos(2x) = 1

Multiply ins * x
insx * n + cos(2x) = 1

Multiply insx * n
in2sx + cos(2x) = 1

Remove parenthesis around (2x)
in2sx + cos * 2x = 1

Reorder the terms for easier multiplication:
in2sx + 2cos * x = 1

Multiply cos * x
in2sx + 2cosx = 1

Reorder the terms:
2cosx + in2sx = 1

Solving
2cosx + in2sx = 1

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1in2sx' to each side of the equation.
2cosx + in2sx + -1in2sx = 1 + -1in2sx

Combine like terms: in2sx + -1in2sx = 0
2cosx + 0 = 1 + -1in2sx
2cosx = 1 + -1in2sx

Divide each side by '2osx'.
c = 0.5o-1s-1x-1 + -0.5in2o-1

Simplifying
c = 0.5o-1s-1x-1 + -0.5in2o-1

Reorder the terms:
c = -0.5in2o-1 + 0.5o-1s-1x-1

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