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x in (-oo:+oo)
sin(x-(pi/3)) = 0
sin(x-(pi/3)) = 0 <=> x-(pi/3) = pi*k_1 i k_1 należy do I
t_1 = pi*k_1
x-t_1-(pi/3) = 0
x-t_1-(pi/3) = 0 // + -t_1-(pi/3)
x = -(-t_1-(pi/3))
x = t_1+pi/3
x = pi*k_1+pi/3 i k_1 należy do I
x = pi*k_1+pi/3
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