solvef(n+1)=f(n)+2n

Solution for solvef(n+1)=f(n)+2n equation:

Simplifying
solvef(n + 1) = f(n) + 2n

Reorder the terms:
eflosv(1 + n) = f(n) + 2n
(1 * eflosv + n * eflosv) = f(n) + 2n

Reorder the terms:
(eflnosv + 1eflosv) = f(n) + 2n
(eflnosv + 1eflosv) = f(n) + 2n

Multiply f * n
eflnosv + 1eflosv = fn + 2n

Solving
eflnosv + 1eflosv = fn + 2n

Solving for variable 'e'.

Move all terms containing e to the left, all other terms to the right.

Reorder the terms:
eflnosv + 1eflosv + -1fn + -2n = fn + -1fn + 2n + -2n

Combine like terms: fn + -1fn = 0
eflnosv + 1eflosv + -1fn + -2n = 0 + 2n + -2n
eflnosv + 1eflosv + -1fn + -2n = 2n + -2n

Combine like terms: 2n + -2n = 0
eflnosv + 1eflosv + -1fn + -2n = 0

The solution to this equation could not be determined.