sqrt(2x+3)-sqrt(x-2)=2

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Solution for sqrt(2x+3)-sqrt(x-2)=2 equation:


Simplifying
sqrt(2x + 3) + -1sqrt(x + -2) = 2

Reorder the terms:
qrst(3 + 2x) + -1sqrt(x + -2) = 2
(3 * qrst + 2x * qrst) + -1sqrt(x + -2) = 2
(3qrst + 2qrstx) + -1sqrt(x + -2) = 2

Reorder the terms:
3qrst + 2qrstx + -1qrst(-2 + x) = 2
3qrst + 2qrstx + (-2 * -1qrst + x * -1qrst) = 2
3qrst + 2qrstx + (2qrst + -1qrstx) = 2

Reorder the terms:
3qrst + 2qrst + 2qrstx + -1qrstx = 2

Combine like terms: 3qrst + 2qrst = 5qrst
5qrst + 2qrstx + -1qrstx = 2

Combine like terms: 2qrstx + -1qrstx = 1qrstx
5qrst + 1qrstx = 2

Solving
5qrst + 1qrstx = 2

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Reorder the terms:
-2 + 5qrst + 1qrstx = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + 5qrst + 1qrstx = 0

The solution to this equation could not be determined.

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