sqrt(2x+5)-sqrt(3x+5)=2

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Solution for sqrt(2x+5)-sqrt(3x+5)=2 equation: 


Simplifying
sqrt(2x + 5) + -1sqrt(3x + 5) = 2

Reorder the terms:
qrst(5 + 2x) + -1sqrt(3x + 5) = 2
(5 * qrst + 2x * qrst) + -1sqrt(3x + 5) = 2
(5qrst + 2qrstx) + -1sqrt(3x + 5) = 2

Reorder the terms:
5qrst + 2qrstx + -1qrst(5 + 3x) = 2
5qrst + 2qrstx + (5 * -1qrst + 3x * -1qrst) = 2
5qrst + 2qrstx + (-5qrst + -3qrstx) = 2

Reorder the terms:
5qrst + -5qrst + 2qrstx + -3qrstx = 2

Combine like terms: 5qrst + -5qrst = 0
0 + 2qrstx + -3qrstx = 2
2qrstx + -3qrstx = 2

Combine like terms: 2qrstx + -3qrstx = -1qrstx
-1qrstx = 2

Solving
-1qrstx = 2

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Divide each side by '-1rstx'.
q = -2r-1s-1t-1x-1

Simplifying
q = -2r-1s-1t-1x-1

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