sqrt(3x+1)+7=2x+1

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Solution for sqrt(3x+1)+7=2x+1 equation:


Simplifying
sqrt(3x + 1) + 7 = 2x + 1

Reorder the terms:
qrst(1 + 3x) + 7 = 2x + 1
(1 * qrst + 3x * qrst) + 7 = 2x + 1
(1qrst + 3qrstx) + 7 = 2x + 1

Reorder the terms:
7 + 1qrst + 3qrstx = 2x + 1

Reorder the terms:
7 + 1qrst + 3qrstx = 1 + 2x

Solving
7 + 1qrst + 3qrstx = 1 + 2x

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + 1qrst + -7 + 3qrstx = 1 + -7 + 2x

Reorder the terms:
7 + -7 + 1qrst + 3qrstx = 1 + -7 + 2x

Combine like terms: 7 + -7 = 0
0 + 1qrst + 3qrstx = 1 + -7 + 2x
1qrst + 3qrstx = 1 + -7 + 2x

Combine like terms: 1 + -7 = -6
1qrst + 3qrstx = -6 + 2x

Reorder the terms:
6 + 1qrst + 3qrstx + -2x = -6 + 2x + 6 + -2x

Reorder the terms:
6 + 1qrst + 3qrstx + -2x = -6 + 6 + 2x + -2x

Combine like terms: -6 + 6 = 0
6 + 1qrst + 3qrstx + -2x = 0 + 2x + -2x
6 + 1qrst + 3qrstx + -2x = 2x + -2x

Combine like terms: 2x + -2x = 0
6 + 1qrst + 3qrstx + -2x = 0

The solution to this equation could not be determined.

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