(-3x+4)/(2)-(-3x+4)/(3) - subtract fractions

Solution for the given fractions

• (4-3*x)/2 - (4-3*x)/3 = ?
• The common denominator of the two fractions is: 6
• (4-3*x)/2 = (3*(4-3*x))/(2*3) = (3*(4-3*x))/6
• (4-3*x)/3 = (2*(4-3*x))/(2*3) = (2*(4-3*x))/6
• Fractions adjusted to a common denominator
• (4-3*x)/2 - (4-3*x)/3 = (3*(4-3*x))/6 - (2*(4-3*x))/6
• (3*(4-3*x))/6 - (2*(4-3*x))/6 = (3*(4-3*x)-(2*(4-3*x)))/6
• (3*(4-3*x)-(2*(4-3*x)))/6 = (3*(4-3*x)-2*(4-3*x))/6

Solution for the given fractions

$ \frac{(4-3*x)}{2 }- \frac{(4-3*x)}{3 }=? $

The common denominator of the two fractions is: 6

$ \frac{(4-3*x)}{2 }= \frac{(3*(4-3*x))}{(2*3)} = \frac{(3*(4-3*x))}{6} $

$ \frac{(4-3*x)}{3 }= \frac{(2*(4-3*x))}{(2*3)} = \frac{(2*(4-3*x))}{6} $

Fractions adjusted to a common denominator

$ \frac{(4-3*x)}{2 }- \frac{(4-3*x)}{3 }= \frac{(3*(4-3*x))}{6 }- \frac{(2*(4-3*x))}{6} $

$ \frac{(3*(4-3*x))}{6 }- \frac{(2*(4-3*x))}{6 }= \frac{(3*(4-3*x)-(2*(4-3*x)))}{6} $

$ \frac{(3*(4-3*x)-(2*(4-3*x)))}{6 }= \frac{(3*(4-3*x)-2*(4-3*x))}{6} $

$ $

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