(1)/(18)-(1)/(9) - subtract fractions

Solution for the given fractions

• 1/18 - 1/9 = ?
• The common denominator of the two fractions is: 18
• 1/18 = (1*1)/(1*18) = 1/18
• 1/9 = (1*2)/(2*9) = 2/18
• Fractions adjusted to a common denominator
• 1/18 - 1/9 = 1/18 - 2/18
• (1-2)/18 = -1/18

Solution for the given fractions

$ \frac{1}{18 }-\frac{ 1}{9 }=? $

The common denominator of the two fractions is: 18

$ \frac{1}{18 }= \frac{(1*1)}{(1*18)} =\frac{ 1}{18} $

$ \frac{1}{9 }= \frac{(1*2)}{(2*9)} =\frac{ 2}{18} $

Fractions adjusted to a common denominator

$ \frac{1}{18 }-\frac{ 1}{9 }=\frac{ 1}{18 }-\frac{ 2}{18} $

$ \frac{(1-2)}{18 }= -\frac{1}{18} $

$ $

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