(26)/(27)-(64)/(81) - subtract fractions

Solution for the given fractions

• 26/27 - 64/81 = ?
• The common denominator of the two fractions is: 81
• 26/27 = (3*26)/(3*27) = 78/81
• 64/81 = (1*64)/(1*81) = 64/81
• Fractions adjusted to a common denominator
• 26/27 - 64/81 = 78/81 - 64/81
• 78/81 - 64/81 = (78-64)/81
• (78-64)/81 = 14/81

Solution for the given fractions

$ \frac{26}{27 }-\frac{ 64}{81 }=? $

The common denominator of the two fractions is: 81

$ \frac{26}{27 }= \frac{(3*26)}{(3*27)} =\frac{ 78}{81} $

$ \frac{64}{81 }= \frac{(1*64)}{(1*81)} =\frac{ 64}{81} $

Fractions adjusted to a common denominator

$ \frac{26}{27 }-\frac{ 64}{81 }=\frac{ 78}{81 }-\frac{ 64}{81} $

$ \frac{78}{81 }-\frac{ 64}{81 }= \frac{(78-64)}{81} $

$ \frac{(78-64)}{81 }=\frac{ 14}{81} $

$ $

see mathematical notation