(3)/(32)-(1)/(16) - subtract fractions

Solution for the given fractions

• 3/32 - 1/16 = ?
• The common denominator of the two fractions is: 32
• 3/32 = (1*3)/(1*32) = 3/32
• 1/16 = (1*2)/(2*16) = 2/32
• Fractions adjusted to a common denominator
• 3/32 - 1/16 = 3/32 - 2/32
• (3-2)/32 = 1/32

Solution for the given fractions

$ \frac{3}{32 }-\frac{ 1}{16 }=? $

The common denominator of the two fractions is: 32

$ \frac{3}{32 }= \frac{(1*3)}{(1*32)} =\frac{ 3}{32} $

$ \frac{1}{16 }= \frac{(1*2)}{(2*16)} =\frac{ 2}{32} $

Fractions adjusted to a common denominator

$ \frac{3}{32 }-\frac{ 1}{16 }=\frac{ 3}{32 }-\frac{ 2}{32} $

$ \frac{(3-2)}{32 }=\frac{ 1}{32} $

$ $

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