(3-x)/(x-5)-(2x+6)/(5-x) - subtract fractions

(3-x)/(x-5)-(2x+6)/(5-x) - step by step solution for the given fractions. Subtract fractions, full explanation.

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    Solution for the given fractions

    • (3-x)/(x-5) - (2*x+6)/(5-x) = ?
    • The common denominator of the two fractions is: (x-5)*(5-x)
    • (3-x)/(x-5) = ((3-x)*(5-x))/((x-5)*(5-x)) = ((3-x)*(5-x))/((x-5)*(5-x))
    • (2*x+6)/(5-x) = ((2*x+6)*(x-5))/((5-x)*(x-5)) = ((2*x+6)*(x-5))/((x-5)*(5-x))
    • Fractions adjusted to a common denominator
    • (3-x)/(x-5) - (2*x+6)/(5-x) = ((3-x)*(5-x))/((x-5)*(5-x)) - ((2*x+6)*(x-5))/((x-5)*(5-x))
    • ((3-x)*(5-x))/((x-5)*(5-x)) - ((2*x+6)*(x-5))/((x-5)*(5-x)) = ((3-x)*(5-x)-((2*x+6)*(x-5)))/((x-5)*(5-x))
    • ((3-x)*(5-x)-((2*x+6)*(x-5)))/((x-5)*(5-x)) = ((3-x)*(5-x)-((2*x+6)*(x-5)))/((x-5)*(5-x))

    Solution for the given fractions

    $ \frac{(3-x)}{(x-5)} - \frac{(2*x+6)}{(5-x)} =? $

    The common denominator of the two fractions is: (x-5)*(5-x)

    $ \frac{(3-x)}{(x-5)} = \frac{((3-x)*(5-x))}{((x-5)*(5-x))} = \frac{((3-x)*(5-x))}{((x-5)*(5-x))} $

    $ \frac{(2*x+6)}{(5-x)} = \frac{((2*x+6)*(x-5))}{((5-x)*(x-5))} = \frac{((2*x+6)*(x-5))}{((x-5)*(5-x))} $

    Fractions adjusted to a common denominator

    $ \frac{(3-x)}{(x-5)} - \frac{(2*x+6)}{(5-x)} = \frac{((3-x)*(5-x))}{((x-5)*(5-x))} - \frac{((2*x+6)*(x-5))}{((x-5)*(5-x))} $

    $ \frac{((3-x)*(5-x))}{((x-5)*(5-x))} - \frac{((2*x+6)*(x-5))}{((x-5)*(5-x))} = \frac{((3-x)*(5-x)-((2*x+6)*(x-5)))}{((x-5)*(5-x))} $

    $ \frac{((3-x)*(5-x)-((2*x+6)*(x-5)))}{((x-5)*(5-x))} = \frac{((3-x)*(5-x)-((2*x+6)*(x-5)))}{((x-5)*(5-x))} $

    $ $

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