(4)/(35)-(7)/(15) - subtract fractions

Solution for the given fractions

• 4/35 - 7/15 = ?
• The common denominator of the two fractions is: 105
• 4/35 = (3*4)/(3*35) = 12/105
• 7/15 = (7*7)/(7*15) = 49/105
• Fractions adjusted to a common denominator
• 4/35 - 7/15 = 12/105 - 49/105
• 12/105 - 49/105 = (12-49)/105
• (12-49)/105 = -37/105

Solution for the given fractions

$ \frac{4}{35 }-\frac{ 7}{15 }=? $

The common denominator of the two fractions is: 105

$ \frac{4}{35 }= \frac{(3*4)}{(3*35)} =\frac{ 12}{105} $

$ \frac{7}{15 }= \frac{(7*7)}{(7*15)} =\frac{ 49}{105} $

Fractions adjusted to a common denominator

$ \frac{4}{35 }-\frac{ 7}{15 }=\frac{ 12}{105 }-\frac{ 49}{105} $

$ \frac{12}{105 }-\frac{ 49}{105 }= \frac{(12-49)}{105} $

$ \frac{(12-49)}{105 }= -\frac{37}{105} $

$ $

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