(4)/(x-2)-(3)/(x+3) - subtract fractions

(4)/(x-2)-(3)/(x+3) - step by step solution for the given fractions. Subtract fractions, full explanation.

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    Solution for the given fractions

    • 4/(x-2) - 3/(x+3) = ?
    • The common denominator of the two fractions is: (x-2)*(x+3)
    • 4/(x-2) = (4*(x+3))/((x-2)*(x+3)) = (4*(x+3))/((x-2)*(x+3))
    • 3/(x+3) = (3*(x-2))/((x+3)*(x-2)) = (3*(x-2))/((x-2)*(x+3))
    • Fractions adjusted to a common denominator
    • 4/(x-2) - 3/(x+3) = (4*(x+3))/((x-2)*(x+3)) - (3*(x-2))/((x-2)*(x+3))
    • (4*(x+3))/((x-2)*(x+3)) - (3*(x-2))/((x-2)*(x+3)) = (4*(x+3)-(3*(x-2)))/((x-2)*(x+3))
    • (4*(x+3)-(3*(x-2)))/((x-2)*(x+3)) = (4*(x+3)-3*(x-2))/((x-2)*(x+3))

    Solution for the given fractions

    $ \frac{4}{(x-2)} -\frac{ 3}{(x+3)} =? $

    The common denominator of the two fractions is: (x-2)*(x+3)

    $ \frac{4}{(x-2)} = \frac{(4*(x+3))}{((x-2)*(x+3))} = \frac{(4*(x+3))}{((x-2)*(x+3))} $

    $ \frac{3}{(x+3)} = \frac{(3*(x-2))}{((x+3)*(x-2))} = \frac{(3*(x-2))}{((x-2)*(x+3))} $

    Fractions adjusted to a common denominator

    $ \frac{4}{(x-2)} -\frac{ 3}{(x+3)} = \frac{(4*(x+3))}{((x-2)*(x+3))} - \frac{(3*(x-2))}{((x-2)*(x+3))} $

    $ \frac{(4*(x+3))}{((x-2)*(x+3))} - \frac{(3*(x-2))}{((x-2)*(x+3))} = \frac{(4*(x+3)-(3*(x-2)))}{((x-2)*(x+3))} $

    $ \frac{(4*(x+3)-(3*(x-2)))}{((x-2)*(x+3))} = \frac{(4*(x+3)-3*(x-2))}{((x-2)*(x+3))} $

    $ $

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