(9)/((7)x)-(1)/(x) - subtract fractions

Solution for the given fractions

• 9/(7*x) - 1/x = ?
• The common denominator of the two fractions is: 7*x^2
• 9/(7*x) = (9*x)/(7*x*x) = (9*x)/(7*x^2)
• 1/x = (1*7*x)/(7*x*x) = (7*x)/(7*x^2)
• Fractions adjusted to a common denominator
• 9/(7*x) - 1/x = (9*x)/(7*x^2) - (7*x)/(7*x^2)
• (9*x)/(7*x^2) - (7*x)/(7*x^2) = (9*x-(7*x))/(7*x^2)
• (9*x-(7*x))/(7*x^2) = (2*x)/(7*x^2)
• (2*x)/(7*x^2) = (2*x^-1)/7

Solution for the given fractions

$ \frac{9}{(7*x)} -\frac{ 1}{x }=? $

The common denominator of the two fractions is: 7*x^2

$ \frac{9}{(7*x)} = \frac{(9*x)}{(7*x*x)} = \frac{(9*x)}{(7*x^2)} $

$ \frac{1}{x }= \frac{(1*7*x)}{(7*x*x)} = \frac{(7*x)}{(7*x^2)} $

Fractions adjusted to a common denominator

$ \frac{9}{(7*x)} -\frac{ 1}{x }= \frac{(9*x)}{(7*x^2)} - \frac{(7*x)}{(7*x^2)} $

$ \frac{(9*x)}{(7*x^2)} - \frac{(7*x)}{(7*x^2)} = \frac{(9*x-(7*x))}{(7*x^2)} $

$ \frac{(9*x-(7*x))}{(7*x^2)} = \frac{(2*x)}{(7*x^2)} $

$ \frac{(2*x)}{(7*x^2)} = \frac{(2*x^-1)}{7} $

$ $

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