(x-9)/(x+9)-(x+1)/(x-9) - subtract fractions

Solution for the given fractions

• (x-9)/(x+9) - (x+1)/(x-9) = ?
• The common denominator of the two fractions is: (x+9)*(x-9)
• (x-9)/(x+9) = ((x-9)*(x-9))/((x+9)*(x-9)) = ((x-9)^2)/((x+9)*(x-9))
• (x+1)/(x-9) = ((x+1)*(x+9))/((x-9)*(x+9)) = ((x+1)*(x+9))/((x+9)*(x-9))
• Fractions adjusted to a common denominator
• (x-9)/(x+9) - (x+1)/(x-9) = ((x-9)^2)/((x+9)*(x-9)) - ((x+1)*(x+9))/((x+9)*(x-9))
• ((x-9)^2)/((x+9)*(x-9)) - ((x+1)*(x+9))/((x+9)*(x-9)) = ((x-9)^2-((x+1)*(x+9)))/((x+9)*(x-9))
• ((x-9)^2-((x+1)*(x+9)))/((x+9)*(x-9)) = ((x-9)^2-((x+1)*(x+9)))/((x+9)*(x-9))

Solution for the given fractions

$ \frac{(x-9)}{(x+9)} - \frac{(x+1)}{(x-9)} =? $

The common denominator of the two fractions is: (x+9)*(x-9)

$ \frac{(x-9)}{(x+9)} = \frac{((x-9)*(x-9))}{((x+9)*(x-9))} = \frac{((x-9)^2)}{((x+9)*(x-9))} $

$ \frac{(x+1)}{(x-9)} = \frac{((x+1)*(x+9))}{((x-9)*(x+9))} = \frac{((x+1)*(x+9))}{((x+9)*(x-9))} $

Fractions adjusted to a common denominator

$ \frac{(x-9)}{(x+9)} - \frac{(x+1)}{(x-9)} = \frac{((x-9)^2)}{((x+9)*(x-9))} - \frac{((x+1)*(x+9))}{((x+9)*(x-9))} $

$ \frac{((x-9)^2)}{((x+9)*(x-9))} - \frac{((x+1)*(x+9))}{((x+9)*(x-9))} = \frac{((x-9)^2-((x+1)*(x+9)))}{((x+9)*(x-9))} $

$ \frac{((x-9)^2-((x+1)*(x+9)))}{((x+9)*(x-9))} = \frac{((x-9)^2-((x+1)*(x+9)))}{((x+9)*(x-9))} $

$ $

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