(1)/(9)-(3)/(15) - subtraction of fractions

Solution for the given fractions

• 1/9 - 3/15 = ?
• The common denominator of the two fractions is: 45
• 1/9 = (1*5)/(5*9) = 5/45
• 3/15 = (3*3)/(3*15) = 9/45
• Fractions adjusted to a common denominator
• 1/9 - 3/15 = 5/45 - 9/45
• 5/45 - 9/45 = (5-9)/45
• (5-9)/45 = -4/45

Solution for the given fractions

$ \frac{1}{9 }-\frac{ 3}{15 }=? $

The common denominator of the two fractions is: 45

$ \frac{1}{9 }= \frac{(1*5)}{(5*9)} =\frac{ 5}{45} $

$ \frac{3}{15 }= \frac{(3*3)}{(3*15)} =\frac{ 9}{45} $

Fractions adjusted to a common denominator

$ \frac{1}{9 }-\frac{ 3}{15 }=\frac{ 5}{45 }-\frac{ 9}{45} $

$ \frac{5}{45 }-\frac{ 9}{45 }= \frac{(5-9)}{45} $

$ \frac{(5-9)}{45 }= -\frac{4}{45} $

$ $

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