(2x)/(3)-(1)/(5) - subtraction of fractions

Solution for the given fractions

• (2*x)/3 - 1/5 = ?
• The common denominator of the two fractions is: 15
• (2*x)/3 = (2*5*x)/(3*5) = (10*x)/15
• 1/5 = (1*3)/(3*5) = 3/15
• Fractions adjusted to a common denominator
• (2*x)/3 - 1/5 = (10*x)/15 - 3/15
• (10*x)/15 - 3/15 = (10*x-3)/15
• (10*x-3)/15 = (10*x-3)/15

Solution for the given fractions

$ \frac{(2*x)}{3 }-\frac{ 1}{5 }=? $

The common denominator of the two fractions is: 15

$ \frac{(2*x)}{3 }= \frac{(2*5*x)}{(3*5)} = \frac{(10*x)}{15} $

$ \frac{1}{5 }= \frac{(1*3)}{(3*5)} =\frac{ 3}{15} $

Fractions adjusted to a common denominator

$ \frac{(2*x)}{3 }-\frac{ 1}{5 }= \frac{(10*x)}{15 }-\frac{ 3}{15} $

$ \frac{(10*x)}{15 }-\frac{ 3}{15 }= \frac{(10*x-3)}{15} $

$ \frac{(10*x-3)}{15 }= \frac{(10*x-3)}{15} $

$ $

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