(4188)/(1000)-(61)/(16) - subtraction of fractions

Solution for the given fractions

• 4188/1000 - 61/16 = ?
• The common denominator of the two fractions is: 2000
• 4188/1000 = (2*4188)/(2*1000) = 8376/2000
• 61/16 = (61*125)/(16*125) = 7625/2000
• Fractions adjusted to a common denominator
• 4188/1000 - 61/16 = 8376/2000 - 7625/2000
• 8376/2000 - 7625/2000 = (8376-7625)/2000
• (8376-7625)/2000 = 751/2000

Solution for the given fractions

$ \frac{4188}{1000 }-\frac{ 61}{16 }=? $

The common denominator of the two fractions is: 2000

$ \frac{4188}{1000 }= \frac{(2*4188)}{(2*1000)} =\frac{ 8376}{2000} $

$ \frac{61}{16 }= \frac{(61*125)}{(16*125)} =\frac{ 7625}{2000} $

Fractions adjusted to a common denominator

$ \frac{4188}{1000 }-\frac{ 61}{16 }=\frac{ 8376}{2000 }-\frac{ 7625}{2000} $

$ \frac{8376}{2000 }-\frac{ 7625}{2000 }= \frac{(8376-7625)}{2000} $

$ \frac{(8376-7625)}{2000 }=\frac{ 751}{2000} $

$ $

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