(4y)/(1)-(3)/(7) - subtraction of fractions

Solution for the given fractions

• (4*y)/1 - 3/7 = ?
• The common denominator of the two fractions is: 7
• (4*y)/1 = (4*7*y)/(1*7) = (28*y)/7
• 3/7 = (1*3)/(1*7) = 3/7
• Fractions adjusted to a common denominator
• (4*y)/1 - 3/7 = (28*y)/7 - 3/7
• (28*y)/7 - 3/7 = (28*y-3)/7
• (28*y-3)/7 = (28*y-3)/7

Solution for the given fractions

$ \frac{(4*y)}{1 }-\frac{ 3}{7 }=? $

The common denominator of the two fractions is: 7

$ \frac{(4*y)}{1 }= \frac{(4*7*y)}{(1*7)} = \frac{(28*y)}{7} $

$ \frac{3}{7 }= \frac{(1*3)}{(1*7)} =\frac{ 3}{7} $

Fractions adjusted to a common denominator

$ \frac{(4*y)}{1 }-\frac{ 3}{7 }= \frac{(28*y)}{7 }-\frac{ 3}{7} $

$ \frac{(28*y)}{7 }-\frac{ 3}{7 }= \frac{(28*y-3)}{7} $

$ \frac{(28*y-3)}{7 }= \frac{(28*y-3)}{7} $

$ $

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