(6r+1)/(3r)-(r-2)/(5r) - subtraction of fractions

Solution for the given fractions

• (6*r+1)/(3*r) - (r-2)/(5*r) = ?
• The common denominator of the two fractions is: 15*r^2
• (6*r+1)/(3*r) = (5*r*(6*r+1))/(3*5*r*r) = (5*r*(6*r+1))/(15*r^2)
• (r-2)/(5*r) = (3*r*(r-2))/(3*5*r*r) = (3*r*(r-2))/(15*r^2)
• Fractions adjusted to a common denominator
• (6*r+1)/(3*r) - (r-2)/(5*r) = (5*r*(6*r+1))/(15*r^2) - (3*r*(r-2))/(15*r^2)
• (5*r*(6*r+1))/(15*r^2) - (3*r*(r-2))/(15*r^2) = (5*r*(6*r+1)-(3*r*(r-2)))/(15*r^2)
• (5*r*(6*r+1)-(3*r*(r-2)))/(15*r^2) = (5*r*(6*r+1)-3*r*(r-2))/(15*r^2)

Solution for the given fractions

$ \frac{(6*r+1)}{(3*r)} - \frac{(r-2)}{(5*r)} =? $

The common denominator of the two fractions is: 15*r^2

$ \frac{(6*r+1)}{(3*r)} = \frac{(5*r*(6*r+1))}{(3*5*r*r)} = \frac{(5*r*(6*r+1))}{(15*r^2)} $

$ \frac{(r-2)}{(5*r)} = \frac{(3*r*(r-2))}{(3*5*r*r)} = \frac{(3*r*(r-2))}{(15*r^2)} $

Fractions adjusted to a common denominator

$ \frac{(6*r+1)}{(3*r)} - \frac{(r-2)}{(5*r)} = \frac{(5*r*(6*r+1))}{(15*r^2)} - \frac{(3*r*(r-2))}{(15*r^2)} $

$ \frac{(5*r*(6*r+1))}{(15*r^2)} - \frac{(3*r*(r-2))}{(15*r^2)} = \frac{(5*r*(6*r+1)-(3*r*(r-2)))}{(15*r^2)} $

$ \frac{(5*r*(6*r+1)-(3*r*(r-2)))}{(15*r^2)} = \frac{(5*r*(6*r+1)-3*r*(r-2))}{(15*r^2)} $

$ $

see mathematical notation