(x)/(7)-(4x-3)/(2) - subtraction of fractions

Solution for the given fractions

• x/7 - (4*x-3)/2 = ?
• The common denominator of the two fractions is: 14
• x/7 = (2*x)/(2*7) = (2*x)/14
• (4*x-3)/2 = (7*(4*x-3))/(2*7) = (7*(4*x-3))/14
• Fractions adjusted to a common denominator
• x/7 - (4*x-3)/2 = (2*x)/14 - (7*(4*x-3))/14
• (2*x)/14 - (7*(4*x-3))/14 = (2*x-(7*(4*x-3)))/14
• (2*x-(7*(4*x-3)))/14 = (2*x-7*(4*x-3))/14

Solution for the given fractions

$ \frac{x}{7 }- \frac{(4*x-3)}{2 }=? $

The common denominator of the two fractions is: 14

$ \frac{x}{7 }= \frac{(2*x)}{(2*7)} = \frac{(2*x)}{14} $

$ \frac{(4*x-3)}{2 }= \frac{(7*(4*x-3))}{(2*7)} = \frac{(7*(4*x-3))}{14} $

Fractions adjusted to a common denominator

$ \frac{x}{7 }- \frac{(4*x-3)}{2 }= \frac{(2*x)}{14 }- \frac{(7*(4*x-3))}{14} $

$ \frac{(2*x)}{14 }- \frac{(7*(4*x-3))}{14 }= \frac{(2*x-(7*(4*x-3)))}{14} $

$ \frac{(2*x-(7*(4*x-3)))}{14 }= \frac{(2*x-7*(4*x-3))}{14} $

$ $

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