t(+3)=(t-2)+2(t-3)

Solution for t(+3)=(t-2)+2(t-3) equation:

t(+3)=(t-2)+2(t-3)

We move all terms to the left:

t(+3)-((t-2)+2(t-3))=0

We add all the numbers together, and all the variables

t3-((t-2)+2(t-3))=0

We add all the numbers together, and all the variables

t^3-((t-2)+2(t-3))=0


We calculate terms in parentheses: -((t-2)+2(t-3)), so:

(t-2)+2(t-3)

We multiply parentheses

(t-2)+2t-6

We get rid of parentheses

t+2t-2-6

We add all the numbers together, and all the variables

3t-8

Back to the equation:

-(3t-8)


We do not support etpression: t^3