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t(-4.5t+1.25)=0
We multiply parentheses
-4t^2+1.25t=0
a = -4; b = 1.25; c = 0;
Δ = b2-4ac
Δ = 1.252-4·(-4)·0
Δ = 1.5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.25)-\sqrt{1.5625}}{2*-4}=\frac{-1.25-\sqrt{1.5625}}{-8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.25)+\sqrt{1.5625}}{2*-4}=\frac{-1.25+\sqrt{1.5625}}{-8} $
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