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t(-t+144)=224
We move all terms to the left:
t(-t+144)-(224)=0
We add all the numbers together, and all the variables
t(-1t+144)-224=0
We multiply parentheses
-1t^2+144t-224=0
a = -1; b = 144; c = -224;
Δ = b2-4ac
Δ = 1442-4·(-1)·(-224)
Δ = 19840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{19840}=\sqrt{64*310}=\sqrt{64}*\sqrt{310}=8\sqrt{310}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(144)-8\sqrt{310}}{2*-1}=\frac{-144-8\sqrt{310}}{-2} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(144)+8\sqrt{310}}{2*-1}=\frac{-144+8\sqrt{310}}{-2} $
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