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t(0.1t-2)=30
We move all terms to the left:
t(0.1t-2)-(30)=0
We multiply parentheses
0t^2-2t-30=0
We add all the numbers together, and all the variables
t^2-2t-30=0
a = 1; b = -2; c = -30;
Δ = b2-4ac
Δ = -22-4·1·(-30)
Δ = 124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{124}=\sqrt{4*31}=\sqrt{4}*\sqrt{31}=2\sqrt{31}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{31}}{2*1}=\frac{2-2\sqrt{31}}{2} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{31}}{2*1}=\frac{2+2\sqrt{31}}{2} $
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