t(225-4.9t)=0

Solution for t(225-4.9t)=0 equation:

t(225-4.9t)=0

We add all the numbers together, and all the variables

t(-4.9t+225)=0

We multiply parentheses

-4t^2+225t=0

a = -4; b = 225; c = 0;
Δ = b2-4ac
Δ = 2252-4·(-4)·0
Δ = 50625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{50625}=225$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(225)-225}{2*-4}=\frac{-450}{-8}
=56+1/4
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(225)+225}{2*-4}=\frac{0}{-8}
=0
$