t(23.2-4.90t)=0

Solution for t(23.2-4.90t)=0 equation:

t(23.2-4.90t)=0

We add all the numbers together, and all the variables

t(-4.9t+23.2)=0

We multiply parentheses

-4t^2+23.2t=0

a = -4; b = 23.2; c = 0;
Δ = b2-4ac
Δ = 23.22-4·(-4)·0
Δ = 538.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23.2)-\sqrt{538.24}}{2*-4}=\frac{-23.2-\sqrt{538.24}}{-8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23.2)+\sqrt{538.24}}{2*-4}=\frac{-23.2+\sqrt{538.24}}{-8}
$