t(33.3-16t)=0

Solution for t(33.3-16t)=0 equation:

t(33.3-16t)=0

We add all the numbers together, and all the variables

t(-16t+33.3)=0

We multiply parentheses

-16t^2+33.3t=0

a = -16; b = 33.3; c = 0;
Δ = b2-4ac
Δ = 33.32-4·(-16)·0
Δ = 1108.89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33.3)-\sqrt{1108.89}}{2*-16}=\frac{-33.3-\sqrt{1108.89}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33.3)+\sqrt{1108.89}}{2*-16}=\frac{-33.3+\sqrt{1108.89}}{-32}
$