t(4t+12)=40

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Solution for t(4t+12)=40 equation:


Simplifying
t(4t + 12) = 40

Reorder the terms:
t(12 + 4t) = 40
(12 * t + 4t * t) = 40
(12t + 4t2) = 40

Solving
12t + 4t2 = 40

Solving for variable 't'.

Reorder the terms:
-40 + 12t + 4t2 = 40 + -40

Combine like terms: 40 + -40 = 0
-40 + 12t + 4t2 = 0

Factor out the Greatest Common Factor (GCF), '4'.
4(-10 + 3t + t2) = 0

Factor a trinomial.
4((-5 + -1t)(2 + -1t)) = 0

Ignore the factor 4.

Subproblem 1

Set the factor '(-5 + -1t)' equal to zero and attempt to solve: Simplifying -5 + -1t = 0 Solving -5 + -1t = 0 Move all terms containing t to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -1t = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -1t = 0 + 5 -1t = 0 + 5 Combine like terms: 0 + 5 = 5 -1t = 5 Divide each side by '-1'. t = -5 Simplifying t = -5

Subproblem 2

Set the factor '(2 + -1t)' equal to zero and attempt to solve: Simplifying 2 + -1t = 0 Solving 2 + -1t = 0 Move all terms containing t to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1t = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1t = 0 + -2 -1t = 0 + -2 Combine like terms: 0 + -2 = -2 -1t = -2 Divide each side by '-1'. t = 2 Simplifying t = 2

Solution

t = {-5, 2}

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