If it's not what You are looking for type in the equation solver your own equation and let us solve it.
t(4t-7)=2
We move all terms to the left:
t(4t-7)-(2)=0
We multiply parentheses
4t^2-7t-2=0
a = 4; b = -7; c = -2;
Δ = b2-4ac
Δ = -72-4·4·(-2)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-9}{2*4}=\frac{-2}{8} =-1/4 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+9}{2*4}=\frac{16}{8} =2 $
| 3=2+b/2 | | -69=7x-20 | | ((B-4)/6)=b2 | | 100=-8x+4 | | -5=-2+v/6 | | X-1.3x=5 | | 6=2x=5x-9x+12 | | 3(3p-1)=-6p-2(-3-6p) | | 5m-13=28 | | 5(-6b+6)+6=6(-3b+2) | | y=1/3(12)+7 | | y=1/3(6)+7 | | -22+5p=-4p+8(3+4p) | | y=1/3(-3)+7 | | 33=-5+2n | | 5x+3.20=18.20 | | 5(r-1)+4=-8+6r | | Y-6=2/5(x+2.5) | | y(3)=-2(3)-11 | | 7(a+5)=32+8a | | z/17=9 | | 14x=16,x | | y(-1)=-2(-1)-11 | | 4×+3y=1×+y=2 | | -8(-4-3p)+2=-38+6p | | 0.6(3+m)=0.8(4-m) | | -8(-4-3p)+2=38+6p | | y(-5)=-2(-5)-11 | | 3=3y+2÷4y+7 | | -1-4(2+7x)=-9-7x | | 8x-27=4x+32 | | -4m-7m=10+8-7m-6 |