t(t+2)(t-2)+2=0

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Solution for t(t+2)(t-2)+2=0 equation: 


Simplifying
t(t + 2)(t + -2) + 2 = 0

Reorder the terms:
t(2 + t)(t + -2) + 2 = 0

Reorder the terms:
t(2 + t)(-2 + t) + 2 = 0

Multiply (2 + t) * (-2 + t)
t(2(-2 + t) + t(-2 + t)) + 2 = 0
t((-2 * 2 + t * 2) + t(-2 + t)) + 2 = 0
t((-4 + 2t) + t(-2 + t)) + 2 = 0
t(-4 + 2t + (-2 * t + t * t)) + 2 = 0
t(-4 + 2t + (-2t + t2)) + 2 = 0

Combine like terms: 2t + -2t = 0
t(-4 + 0 + t2) + 2 = 0
t(-4 + t2) + 2 = 0
(-4 * t + t2 * t) + 2 = 0
(-4t + t3) + 2 = 0

Reorder the terms:
2 + -4t + t3 = 0

Solving
2 + -4t + t3 = 0

Solving for variable 't'.

The solution to this equation could not be determined.

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